7m^2+48m+30=7m

Solution for 7m^2+48m+30=7m equation:

7m^2+48m+30=7m

We move all terms to the left:

7m^2+48m+30-(7m)=0

We add all the numbers together, and all the variables

7m^2+41m+30=0

a = 7; b = 41; c = +30;
Δ = b2-4ac
Δ = 412-4·7·30
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-29}{2*7}=\frac{-70}{14}
=-5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+29}{2*7}=\frac{-12}{14}
=-6/7
$